Equation of a parallel line (help)

Q) write the equation of a line that is parallel to the line 2x - 4y = 8 and goes through the point (3,0)

I rearranged in the form y=mx + c and got y= 1/2x - 2

Then I work out the equation of the parallel line by doing this right? y-y1 = 1/2 (x-x1)

so its y-0 = 1/2 (x-3)

and I got y= 2x - 3

and its wrong

It was all perfect until the very last bit! y = 1/2 ( x - 3 ) becomes:y = x/2 - 3/2

don't we x by 2 and expand the bracket?

That was the expansion of the bracket. The 1/2 got multiplied by all elements inside the bracket

don't we x by 2 and expand the bracket?

It's the same thing but it can just make it easier in some cases by allowing you to work with whole numbers rather than fractions. If you did multiply by 2 the answer should be 2y=x-3.

wouldn't i multiply the whole equation not just 2y?

That's what I meant. If you double y-0=1/2(x-3) it comes out to 2y=1(x-3) and obviously you don't need to expand it so it just becomes 2y=x-3.

I get it so we can do it either way, I just made the mistake by x 2 by x when it was 1/2

Yh sometimes the question will ask for integers so you can't always leave it as a fraction.

we just divide so we get rid of the fraction?

X the whole equation by the denominator so when you had the one with 1/2x you x it all by 2.