maths question.

15) The equation of line L1 is y=2x-5

The equation of L2 is 6y + kx-12=0
L is perpendicular to L2
find the value of k
must show your working

Reply 1

auroraflight

Original post by mussadis.iqbal

15) The equation of line L1 is y=2x-5
The equation of L2 is 6y + kx-12=0
L is perpendicular to L2
find the value of k
must show your working

There is a link between the gradients of two perpendicular lines. Hope that helps? if you need any more hints just ask!

Reply 2

chloesj

Original post by mussadis.iqbal

15) The equation of line L1 is y=2x-5
The equation of L2 is 6y + kx-12=0
L is perpendicular to L2
find the value of k
must show your working

If you rearrange L2 into y = mx + c form and know that the gradients of perpendicular lines are the same, you should be able to work out k. does that make sense?

Reply 3

old_engineer

Original post by chloesj

If you rearrange L2 into y = mx + c form and know that the gradients of perpendicular lines are the same, you should be able to work out k. does that make sense?

I think you’ll find it’s parallel lines that have the same gradient…