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FP1 Invariant Points Help Required

The matrix T maps [br](xy)[br]\begin{pmatrix} x \\ y \end{pmatrix} onto

[br](acbd)(xy)[br][br]\begin{pmatrix} a & c \\ b & d \end{pmatrix} \begin{pmatrix} x \\ y \end{pmatrix}[br] Hence show that invariant points other than the origin exist if Det(T) = a + d -1. I said that x=ax+cyx = ax + cy and y=bx+dy y= bx + dy and that therefore a=1, c=0, b=0, d=1. I don't understand how I can find the determinate of T from this.
(edited 7 years ago)
Original post by Shipreck
The matrix T maps [br](xy)[br]\begin{pmatrix} x \\ y \end{pmatrix} onto

[br](acbd)[br](xy)[br][br]\begin{pmatrix} a & c \\ b & d \end{pmatrix} *[br]\begin{pmatrix} x \\ y \end{pmatrix} [br]

[br][br]


wat
Reply 2
Original post by RDKGames
wat


Pressed submit while still figuring the latex out. Lmao sorry.
Reply 3
Original post by RDKGames
wat


fixed
Original post by Shipreck
The matrix T maps [br](xy)[br]\begin{pmatrix} x \\ y \end{pmatrix} onto

[br](acbd)(xy)[br][br]\begin{pmatrix} a & c \\ b & d \end{pmatrix} \begin{pmatrix} x \\ y \end{pmatrix}[br] Hence show that invariant points other than the origin exist if Det(T) = a + d -1. I said that x=ax+cyx = ax + cy and y=bx+dy y= bx + dy and that therefore a=1, c=0, b=0, d=1. I don't understand how I can find the determinate of T from this.


If you solve the simultaneous equations that you have set out as

x=ax+cy \displaystyle x = ax + cy
y=bx+dy\displaystyle y= bx + dy

and crunch the algebra, you should arrive at the equation

adbc=a+d1 \displaystyle ad - bc = a + d - 1

The left hand side of this is the determinant of T.

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