The Student Room Group

Mechanics 1 question a bit stuck!

Ok, so i got the first two parts completely correct, but i dont get how to prove the third part.

A particle of mass M kg slides down a rough plane which is inclined at 30 degree to the horizontal. The particle passes through a point A with speed 4ms, and two seconds later it passes through a point B with speed 9ms.

i) Find the acceleration of the particle
Using suvat, correct answer of 2.5ms-2 !

ii) find the distance AB
following up suvat
s=13m

iii) Show that the frictional force on the particle is 2.4M newtons??

I have resolved it and have used f = ma with not much success, then f=uR but i assume you dont need that yet as the last part asks you to find the co-efficient of friction. Im sure its easy, help appreciated!
Dont you use sin theta something or other?

Or use an angle I mean.
Reply 2
well using f=ma
i got

Mgsin30 - F(friction) = 0.25M
But that doesnt equal 2.4M ???? :biggrin:
Reply 3
Mgsin30 - F = 2.5M

Since sin30=1/2

0.5Mg - F = 2.5M

Since g=9.8

4.9M - F = 2.5M

F=(4.9-2.5)M
F=2.4M

Latest