Solving Equations

Two tricky equations

No.1
4x = 3x / x squared - 12
Give answer as a surd

No.2 Solve these simulataneous equations
a + 2b + 3c = -1
3a + 4b + 4c = -2
2a - 5b + c = 20

Reply 1

sophie_c

10

Heya
Can you put some brackets in the first one? Ie is it (3x/x)^2 or 3x/(x^2)?

No. 2= a=2, b=-3 and c=1
If you need I could type out the working for this

Hope that's some help :smile:

Reply 2

Illusionary

19

rrcbein

Two tricky equations

No.1
4x = 3x / x squared - 12
Give answer as a surd

No.2 Solve these simulataneous equations
a + 2b + 3c = -1
3a + 4b + 4c = -2
2a - 5b + c = 20

1.

I'm going to assume that you mean 4x = 3x / (x^2 - 12). Start by multiplying the whole equation through by (x^12 - 12). Does that give you a form that you're happier to attempt to solve?

2.

You need to eliminate terms in sequence by combining the equations together. As an example, (eq.2)-(eq.1)-(eq.3) gives:
0a + 7b + 0c = -21.

sophie_c

If you need I could type out the working for this

I know you mean well with this offer, but we don't generally allow full solutions to be posted, as this limits the opportunity for people asking questions to learn how to apply techniques themselves. :smile:

Reply 3

sophie_c

10

Illusionary

I know you mean well with this offer, but we don't generally allow full solutions to be posted, as this limits the opportunity for people asking questions to learn how to apply techniques themselves. :smile:

Okeydoke, sorry :o:

Solving Equations

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