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binomial expansion c4

Hello I am a little bit stuck on this question:


Obtain the first four NON ZERO terms in ascending powers of x in the expansion:

1 /(Square root of (1-2x^2) )

and the question also gives that 2x^2<1

I cant understand why the answer is 1 + x^2 + (3/2)x^4 + (5/2)x^5

arghh help me pls??
many thanks
Reply 1
Did you write as (1-2x^2)^(-0.5) and then use the expansion with n=-0.5 and replace x by -2x^2.
Reply 2
Original post by vc94
Did you write as (1-2x^2)^(-0.5) and then use the expansion with n=-0.5 and replace x by -2x^2.


spot on! I mixed up the 2X^2 haha thanks

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