The Student Room Group
You forget to divide your answer through by z?
KAISER_MOLE
You forget to divide your answer through by z?


what ya mean? :confused:
Reply 3
I dont understand your working at all, looks like youre just calculating z^2 + 2

can you confirm if the questio is z + (2/z) or (z + 2)/z?
john!!
I dont understand your working at all, looks like youre just calculating z^2 + 2

can you confirm if the questio is z + (2/z) or (z + 2)/z?


z+ (2/z)

i just subbed in z
Reply 5
z+2/z

=-1+3i +2/(-1+3i)
=-1+3i + 2(-1-3i)/((-1+3i)(-1+3i))
=-1+3i + (-2-6i)/7
=-9/7 +15i/7
Reply 6
you just multiplied the numerator by the conjugate and the denominator by z.
ok i understand that to rationalise (5+6i)/(4-3i) you times both by (4+3i) but im not too sure as to what you did here:

=-1+3i +2/(-1+3i)
=-1+3i + 2(-1-3i)/((-1+3i)(-1+3i))

doesnt one of those bottom (-1+3i)'s need to be -3i in order to rationalise?? :confused:
Reply 8
(-1+3i) + 2/(-1+3i)
((-1+3i)^2 + 2)/(-1+3i)
(-(6 + 6i))/(-1+3i)
(-(6 + 6i)(-1-3i)/10
(-12 + 24i)/10
-(6/5) + (12/5)i
Vazzyb
(-1+3i) + 2/(-1+3i)
((-1+3i)^2 + 2)/(-1+3i)
(-(6 + 6i))/(-1+3i)
(-(6 + 6i)(-1-3i)/10
(-12 + 24i)/10
-(6/5) + (12/5)i


surely tho when you times both sides by (-1+3i) you get rid of the (-1+3i) underneath the 2?? :redface:
Reply 10
a + (2/a) -> a^2/a + 2/a => (a^2 + 2)/a

that is the question isn't it?
Vazzyb
a + (2/a) -> a^2/a + 2/a => (a^2 + 2)/a

that is the question isn't it?


i see what uve done me old chum! lol
Reply 12
there are no "both sides", its an expression not an equation. thats probably where you went wrong originally.
Reply 13
Exactly what I was thinking. All those statements need to be equal for it to be valid.

You wrote:
(-1+3i)+2/(-1+3i)
(-1+3i)²+2

Are you saying z + 2/z = + 2 ? I hope not.

Latest