C3 (Not MEI) - Thursday June 14 2012, AM

I found it round the x axis NOOOOOOO ='(
That means I would have lost like the full 8 marks.

How did you have to do question 9iii) ?? i got the 9ii right but i dont know what i did for the last bit :/

Jan 11: A* 59, A 52, B 45 100 UMS: 66
June 10: A* 56, A 50, B 44 100 UMS: 62
June 11: A* 58, A 52, B 46 100 UMS: 64
Jan 12: A* 61, A 54, B 47 100 UMS: 68

Where A* = 90 UMS

A* Based on the difference between A and B added to mark for A
100 UMS grade boundary based on twice the difference between A and B

Based on this, I would say 60 is about 85-95 UMS

Okay, i've now managed to remember all of my answers.
Do people generally agree with this?:

- x<4/3 and x>6

- (ep^2)/q = 261
- 5^n > pq, smallest integer n = 361 (n > 360.4)

- tan = 6
- tan(alpha - 45) = 5/7
- tan(2xalpha) = -12/35

- normal ln graph (stretched scale factor k, but i wouldn't think this would need to be indictaed)
AND x^2 graph, reflected in the x axis crossing y at -14 (I got this wrong - forgot to reflect in y axis so I put y=x^2 crossing y axis at +14))
- I didn't really know what to do for part 2, so i rearragned the equation to f(x) = X^2 + 3lnx - 14.
Then I subbed 2,3 and 4 for x, and found a sign change between 3 and 4, so put: 3 < alpha < 4
- alpha = 3.24 (2 dp)

[fg(x)]:
- alpha = 4
- X = -1/2

- integrate (e^x + 2)^2 = 1/2(e^2 + 8e - 1) (I think I put this)

- dv/dh = 12.17
- dv/dt = 0.183 (3 sf)

- 5sin(theta + 53.1)
- theta = -64.6, 138.4
- k=8, c=3

- Differentiates to ln(2y)
- (pi/2)(3e^4 + 1)
- (pi/2)(e^4 - 1)

If anybdy feels down from todays exam, here's something for you:

[video="youtube;2J5xs2ukksE"]http://www.youtube.com/watch?v=2J5xs2ukksE[/video]

AND x^2 graph, reflected in the x axis crossing y at -14 (I got this wrong - forgot to reflect in y axis so I put y=x^2 crossing y axis at +14))

I thought the equation of the line was y=14 - x^2? It would cross the y-axis at y=14 when x=0 right?

I thought the equation of the line was y=14 - x^2? It would cross the y-axis at y=14 when x=0 right?

Oh course, my bad.
That means I might only lose 1 mark for that question because I marked (0, 14)

why would you lose a mark for that?

I'll fix that for you

[video="youtube;nUuggXTCNJE"]http://www.youtube.com/watch?v=nUuggXTCNJE&feature=my_liked_videos&list=LLsiYmze_-n1RgkvlXz2IzXw[/video]

I didn't flip y=x^2 in the x axis, so (0,14) was the minimum point on my graph, not the maximum

In your opinion, with reference to 9ii), if you calcuated the wrong volume in 9i) but used that volume in 9ii) would you get follow through marks? If so, how many of the 2?