AS level maths - logs help!

Heey,
how do you work out log x =2log5 + log1 -2?

Heey,
how do you work out log x =2log5 + log1 -2?

you use the laws of logs

log(a)+log(b) = log(ab)

log(a)-log(b) = lo(a/b)

log(c^d) = dlog(c)

n = nlog(10)

when it says log like that it means log of base 10. Literally type it into your calculator and you should get the answer

you use the laws of logs

log(a)+log(b) = log(ab)

log(a)-log(b) = lo(a/b)

log(c^d) = dlog(c)

n = nlog(10)

Yeaah so it'll be log x = log (5^2 x 1) -2
but what do you do after that?

Yeaah so it'll be log x = log (5^2 x 1) -2
but what do you do after that?

you need a single log

You need to turn the 2 into a log also

you need a single log

You need to turn the 2 into a log also

And then do you divide by log or something?

And then do you divide by log or something?

you take the anti-log

If log(a) = log(b)

then a=b

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