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C4 trigs

2sin2x = cosx
4sinxcosx = cosx
cannot divide by cosx because some values are lost




sinx=cos(x+120)
sinx=cosxcos120-sinxsin120
sinx=-0.5cosx-(sqrt(3)/2)sinx
2sinx=-cosx-sqrt(3)sinx
Here you have to divide by cosx in order for the result to be solved

How am I supposed to know when dividing will cause some roots to be lost or not?
Reply 1
Original post by helpme456
2sin2x = cosx
4sinxcosx = cosx
cannot divide by cosx because some values are lost




sinx=cos(x+120)
sinx=cosxcos120-sinxsin120
sinx=-0.5cosx-(sqrt(3)/2)sinx
2sinx=-cosx-sqrt(3)sinx
Here you have to divide by cosx in order for the result to be solved

How am I supposed to know when dividing will cause some roots to be lost or not?


Always try to factorize wherever possible.

Your first problem can be written as (something) X cos x = 0, so either cox x = 0 or something = 0 and you have to check both possibilities.

Your second problem is of the form a sinx = bcos x. If cos x were 0 then sin x would have to be 0 too, but there are no angles for which this is true, so it is safe to divide by cos x.
Reply 2
Original post by helpme456
2sin2x = cosx
4sinxcosx = cosx
cannot divide by cosx because some values are lost

Rearrange.

Just lkke if you were trying to solve
x22=x x^2 - 2 = x you would take x away frm both sides:
x22x=0[br]x2x2=0 x^2 - 2 -x = 0 [br]x^2 - x - 2 = 0 and then you would factorise.
Use similar methods with
4sin(x)cos(x)=cos(x) 4sin(x)cos(x) = cos(x)

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