Differentiation help

I am trying to find dh/dt
So why can’t I use the chain rule of dh/dt instead I have to use it on dv/dt how do you figure out on which change of rate you use the chain rule on?

Also what property is it talking about below?

Reply 1

atsruser

Original post by IShouldBeRevising_

I am trying to find dh/dt
So why can’t I use the chain rule of dh/dt instead I have to use it on dv/dt how do you figure out on which change of rate you use the chain rule on?

Also what property is it talking about below?

\frac{dV}{dt} = \frac{dV}{dh} \frac{dh}{dt}

You are given

\frac{dV}{dt}

numerically in the question. You can find

\frac{dV}{dh}

from the functional relationship given.

The log relationship is:

\log(\frac{a}{b}) = \log(a) - \log(b)

Quick Reply

Latest

Articles for you

Edexcel A-Level Economics Paper 1 - Unofficial Mark Scheme - 18 May 2023

Bmat: when it is, what it costs and how to prepare

What is an LLM and how could it benefit your career?

Powerful questions business students forget to ask their career advisers

Differentiation help

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you