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Atholruston

How do I find the equation of the normal to the curve y=e^x(cosx+sinx) at the point (0,1)

Reply 1

Kvothe the Arcane

Original post by Atholruston

How do I find the equation of the normal to the curve y=e^x(cosx+sinx) at the point (0,1)

by differentiating. subbing in x=0 into

\dfrac{dy}{dx}

and then taking the negative multiplicative inverse of that to obtain the normal gradient and then using the formula

y-y_1=m(x-x_1)

Reply 2

davros

Original post by Atholruston

How do I find the equation of the normal to the curve y=e^x(cosx+sinx) at the point (0,1)

The normal is perpendicular to the tangent at that point, so first follow your usual procedure to find the gradient of the tangent, then work out the equation of a line that has a perpendicular gradient and passes through (0,1).

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