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Integration help !!

How would i got about integrating

2x(1-x)^7 Any help would be great thanks


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Reply 1
let u=1-x,x=1-u integration by substitutution
Reply 2
Original post by adl24
How would i got about integrating

2x(1-x)^7 Any help would be great thanks


Posted from TSR Mobile



Original post by rainbowzhu
let u=1-x,x=1-u integration by substitutution


I would have used Integration By Parts, but that is just a personal preference
Reply 3
Original post by adl24
How would i got about integrating

2x(1-x)^7 Any help would be great thanks


Posted from TSR Mobile


2x(1x)7=(2x2+2)((1x)7=2(1x)(1x)7+2(1x)7=2(1x)72(1x)82x\cdot (1-x)^7=(2x-2+2)(\cdot (1-x)^7=-2(1-x)(1-x)^7+2(1-x)^7=2(1-x)^7-2(1-x)^8

and for integration of (1-x)^n use

(ax+b)ndx=(ax+b)n+1a(n+1)+C\displaystyle \int (ax+b)^n dx=\frac{(ax+b)^{n+1}}{a\cdot (n+1)}+C
(edited 10 years ago)

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