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Parametric Integration

What am I doing wrong in this part b question? Please help.

Posted from TSR Mobile
At a glance it would appear you are integrating along the wrong axis. You should have something of the form:

R=π06x2dyR = \pi \int^{6}_{0} x^2 dy

Hopefully that sorts it out.

Original post by ialexxd
What am I doing wrong in this part b question? Please help.

Posted from TSR Mobile
Original post by ialexxd
What am I doing wrong in this part b question? Please help.


Whilst the calculation you have done is necessary, it does not correspond to the region R being rotated.

What region does it correspond to? Have at think.
Reply 3
Original post by WishingChaff
At a glance it would appear you are integrating along the wrong axis. You should have something of the form:

R=π06x2dyR = \pi \int^{6}_{0} x^2 dy

Hopefully that sorts it out.


Why is it x^2 dy? That's the bit I don't understand

Posted from TSR Mobile
(edited 10 years ago)
Reply 4

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