circuits

http://filestore.aqa.org.uk/subjects/AQA-PHYA1-W-QP-JUN11.PDF

Could someone help me on 6ci) please?

Thanks!

R = V/I

and since the graph is V (y axis) vs I (x-axis), the gradient of the line represents resistance.

So if the resistance doubles, the gradient also doubles.

The new resistance line will start at the same pd (1.5V) on the y-axis and pases through the point 0.4V/1.25A. Chosen because the point 0.4V/2.5A is conveniently placed on the original line.

Oh, but how would i work out the new gradient, how do you know it crosses 0.4/1.25?

Thanks!