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finding the "value" of an equation

Hi,

I've been given the equation:

y=3x3π2sinxy = 3x - \dfrac{3\pi}{2}\sin{x}

And I've been asked to show that the minimum value of this is:

3arccos2π32π243\arccos{\dfrac{2}{\pi}} - \dfrac{3}{2}\sqrt{\pi^2 -4}

I was quite confused by this at first as I kept finding the x coordinate at the minimum which is:

arccos2π\arccos{\dfrac{2}{\pi}}

When I thought to find the y value at the minimum it turned out to be what they wanted.

My question is, is it always the case that when the question says "value", they are looking for the y coordinate, not the x?

Thank you :smile:
Original post by so it goes

My question is, is it always the case that when the question says "value", they are looking for the y coordinate, not the x?

Thank you :smile:


Yes: When you evalueate a function you're plugging in an "x" and working out the "y", the value of the function.
Reply 2
Original post by ghostwalker
Yes: When you evalueate a function you're plugging in an "x" and working out the "y", the value of the function.


Ahh, thank you! I can't believe I've come this far without realising that :eek:

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