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Quick dihedral question

Hi for a dihedral group where r represents a rotation and s a reflection what does rs mean?

Is it a rotation followed by a reflection?

Or a reflection followed by a rotation?

Thanks!


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Reply 1
also is the rotation r clockwise or anticlockwise?

Thanks


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Original post by number23
Hi for a dihedral group where r represents a rotation and s a reflection what does rs mean?

Is it a rotation followed by a reflection?

Or a reflection followed by a rotation?

Thanks!

We consider them to be like functions acting on the polygon. Hence rsrs means "perform s, then r" - that is, it's the reflection and then the rotation. Much like fg(x)fg(x) is f applied to g(x)g(x).


Original post by number23
also is the rotation r clockwise or anticlockwise?

It doesn't really matter - just pick a direction and stick to it. I'm not even aware of a convention about this, because it turns out to be quite rare in practice that the orientation of the rotation matters. After all, if you define it one way, I can always look from the "other side of the table" (picture: you've drawn the shape on a glass table with rotation defined clockwise; I crawl under the table and look up, and see the same shape with the same transformations but with rotation defined anticlockwise).
Reply 3
Original post by Smaug123
We consider them to be like functions acting on the polygon. Hence rsrs means "perform s, then r" - that is, it's the reflection and then the rotation. Much like fg(x)fg(x) is f applied to g(x)g(x).



It doesn't really matter - just pick a direction and stick to it. I'm not even aware of a convention about this, because it turns out to be quite rare in practice that the orientation of the rotation matters. After all, if you define it one way, I can always look from the "other side of the table" (picture: you've drawn the shape on a glass table with rotation defined clockwise; I crawl under the table and look up, and see the same shape with the same transformations but with rotation defined anticlockwise).


Thanks I've done a few practice questions and it doesn't seem like orientation does not matters.

Also, if you were asked to find the conjugacy classes for a group, say S3, is there a quick way to do this? Do you find the class for each elements and perform all the cycle multiplications (because this takes me forever)?

Thanks so much!


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Original post by number23
Also, if you were asked to find the conjugacy classes for a group, say S3, is there a quick way to do this? Do you find the class for each elements and perform all the cycle multiplications (because this takes me forever)?

There is a theorem about this. Do you know the theorem that "KK is a conjugacy class in SnS_n iff all elements of KK share the same cycle type and no other elements from SnKS_n - K have that cycle type"?
Reply 5
Original post by Smaug123
There is a theorem about this. Do you know the theorem that "KK is a conjugacy class in SnS_n iff all elements of KK share the same cycle type and no other elements from SnKS_n - K have that cycle type"?


Ah ok, so the conjugacy class of a permutation with a certain shape is the set of all elements with that shape

Thanks I get it now


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