Year 12s: what will be the first way you research your future options? >>

Further Maths- equations of lines

I'm stuck, the question is... Find an equation of the line parallel to 3x-4y=7 passing through (2,-3).
Can anyone help?

1. Find the gradient of the line.
Put the y term on one side and the rest on the other. Then divide by 4 to yet y = 3/4 x - 7/4
2. Use the equation y - y1 = m(x - x1).
You get y + 3 = 3/4(x - 2)
3. Simplify.
4y + 12 = 3x - 6
3x - 4y - 18 = 0

Reply 2

Super199

Original post by Bobby21231

I'm stuck, the question is... Find an equation of the line parallel to 3x-4y=7 passing through (2,-3).
Can anyone help?

Put the equation of line in the form y=mx+c
Since the line is parallel the gradient will be the same so m in this case
Then use the equation of line ---> y-y1=m(x-x1) Where x1 and y1 are the points it passes through.

:smile:

Reply 3

CC21231

Thankyou very much you hav been very helpful

Reply 4

davros

Original post by Bobby21231

I'm stuck, the question is... Find an equation of the line parallel to 3x-4y=7 passing through (2,-3).
Can anyone help?

I think you've solved it now, but note that you don't need to rearrange the original equation at all!

3x - 4y = 10 is a line parallel to 3x - 4y =7. So is 3x - 4y =3. So is 3x - 4y = 125.

Can you see how to choose a line that is parallel to 3x-4y = 7 and includes the point you're given?