Original post by Nausicaax
Solve the following equations for values of theta in the range 0-180degrees
cos (60+theta) =sin (theta)
can anyone show me how to do this please? Can't find any help on Google and its in for tomorrow
(I'm an idiot)
cos (60+theta) =sin (theta)
can anyone show me how to do this please? Can't find any help on Google and its in for tomorrow
(I'm an idiot)
Expand the left hand side and divide tthrough by tan(theta)
Original post by brianeverit
Expand the left hand side and divide tthrough by tan(theta)
So I expanded and got
1/2 cos theta- (route3)/2 sin theta = sin theta
(sorry, Im really bad at this stuff)
Original post by Nausicaax
Done it! Thanks for the help x
No problem. Glad you got there.
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