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Inequalities help please

How would I know that the | (x^2*y)/ (x^2+y^2)| <= |y| ?

Thank you

Flip the fraction.
Switch the inequality sign.
Multiply by the modulus of y.
Separate numerator on left to two fractions.
Remove modulus.
And you are sorted.

Bish.Bash.Bosh.

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Reply 2

Skαteboαrder

\displaystyle \bigg|\frac{x^2y}{x^2+y^2} \bigg| \le \bigg|\frac{x^2y+y^3}{x^2+y^2} \bigg|= \bigg|\frac{y(x^2+y^2)}{x^2+y^2} \bigg|= |y|.

Reply 3

Vorsah

Original post by Xin Xang

Flip the fraction.
Switch the inequality sign.
Multiply by the modulus of y.
Separate numerator on left to two fractions.
Remove modulus.
And you are sorted.

Bish.Bash.Bosh.

Posted from TSR Mobile

Original post by Skαteboαrder