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Differentiate Sin^2(4x)

Hello

I am writing out some Core 4 notes and i'm not sure on the working for this:

d/dx( Sin^2(4x))

= 4sin8x

If someone could explain that would be great

Thank you :biggrin:DDD
Original post by Ammy97
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Chain rule then double angle formulae.
Original post by Ammy97
Hello

I am writing out some Core 4 notes and i'm not sure on the working for this:

d/dx( Sin^2(4x))

= 4sin8x

If someone could explain that would be great

Thank you :biggrin:DDD


That is not correct. ddxsin24x=8sin4xcos4x \frac{\text{d}}{\text{d}x}\sin^24x=8\sin4x\cos4x
Original post by brianeverit
...


2sin4xcos4x=sin8x 2 \sin 4x \cos 4x = \sin 8x
Reply 4
Original post by Ammy97
Hello

I am writing out some Core 4 notes and i'm not sure on the working for this:

d/dx( Sin^2(4x))

= 4sin8x

If someone could explain that would be great

Thank you :biggrin:DDD


You know that cos(2A)=12sin2A\cos(2A) = 1 - 2\sin^2A
and so sin2A=(1/2)(1cos2A)\sin^2 A = (1/2)(1 - \cos2A)

Therefore

sin2(4x)=(1/2)(1cos(8x))\sin^2 (4x) = (1/2)(1 - \cos(8x))

Now differentiate :smile:

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