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I need help with d. I have p(A)= 0.54 and p(B)= 0.33 p(AnB)= 0.22. How do I show they're independent?

Original post by jadechapell

I need help with d. I have p(A)= 0.54 and p(B)= 0.33 p(AnB)= 0.22. How do I show they're independent?

You have to multiply P(A)XP(B) an if that =0.22 the are independent

To clarify, the general condition for independence is:
P (A intersection B) = P (A) * P (B)

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You have to multiply P(A)XP(B) an if that =0.22 the are independent

It doesn't equal 0.22 though. Have I done something else wrong?

Original post by jadechapell

It doesn't equal 0.22 though. Have I done something else wrong?

Not necessarily.

If P(A) x P(B) = P(A n B) then they are independent. If this isn't true then they're not.

Not necessarily.

If P(A) x P(B) = P(A n B) then they are independent. If this isn't true then they're not.

Okay thank you, for some reason I thought if it wasn't mutually exclusive it had to be independent.

Original post by jadechapell

It doesn't equal 0.22 though. Have I done something else wrong?

No it just means they aren't independent

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