The Student Room Group
Reply 1
Mass has no effect if air resistance is negligible - but that is not the case here.


The air resistance of the two is the same - but the weight of the lead is much greater.

This means that the resultant force downward is much bigger for the lead - so its acceleration will be bigger. (and its terminal velocity is higher if they fall far enough)
Reply 2
I'm not convinced. Could you go over that in more detail please?
Reply 3
jamesgurung
I'm not convinced. Could you go over that in more detail please?


Right, in order to find the acceleration, you resolve downwards:

mg - F = ma

a = g - F/m

Where m is the mass, F is the force of air resistance and a is the acceleration.

Since they are the same shape, F is the same for both.

However since the mass of the lead ball is greater, F/m is smaller, hence a is greater and so it falls 'faster' than the tennis ball.
Reply 4
F = ma = mg

a = g
Reply 5
Robob
a = g - F/m

Thanks, I understand. And I assume this holds even in a more realistic model with F a function of velocity.

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