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Help on electromagnetic induction

Hey I have the question
The coil of an ac generator has 80 turns, a length of 65mm and a width of 38mm. It spins in a uniform magnetic field of flux density 130mT at a constant frequency of 50Hz.
Calculate the magnetic flux density-which is 26mWb
Show each side of the coil moves at a speed of 6.0ms^-1 which i used v=wπf
show that the peak voltage is 8.1V

I cant find any eqaution to find the asnwer. Seen on another thread from years ago that it should contain the angular velocity, the flux density, the dimensions of the coil and the number of turns. Can anyone give me the equation I need to use?

Reply 1

atsruser

Original post by michaela holmes

I cant find any eqaution to find the asnwer. Seen on another thread from years ago that it should contain the angular velocity, the flux density, the dimensions of the coil and the number of turns. Can anyone give me the equation I need to use?

By Faraday's law

|E|=|\frac{d\Phi}{dt}|

.

The flux linkage with the coil when its normal makes an angle

\theta

with the B field is

\Phi = NAB\cos\theta

.

Can you do the rest?

Reply 2

Lorenzominga15

No i still don’t get it , can you show the full working out

Reply 3

Eimmanuel

Study Forum Helper

Original post by Lorenzominga15

No i still don’t get it , can you show the full working out

Say what you don’t get. By giving you the full working does not really allow you to think and understand the problem.

IMO, atsruser had provided the “full” solution and it is a matter of filling in the physical quantities.

Below is a video that describes the essential principles or concepts that you need for the problem. NOT the best but I think it does the job. :smile: