trisection - solution
FIRST PART
AB divider, circuit 1 (c pictured), AG (Analytical Geometry)
Ruler, the line referred to in Section A and B ( pictured) , AG provided the point D (intersection circle 1 and line )
Divider AB from point D cuts the line and afforded the point E
Bisection angle DAB, a point C
Ruler, the line referred to in Section B and C (b pictured), AG
slika 1.png
AB divider, circuit 1 (c pictured), AG (Analytical Geometry)
Ruler, the line referred to in Section A and B ( pictured) , AG provided the point D (intersection circle 1 and line )
Divider AB from point D cuts the line and afforded the point E
Bisection angle DAB, a point C
Ruler, the line referred to in Section B and C (b pictured), AG
slika 1.png
SECOND PART
Divider AB, at point A (arm angle rotates around point C), from point B to create a circle 2 (g pictured), AG
Divider BC, at point B, cut the circle 2, we get the point F
Ruler, line through the points A and F, AG
112.png
Divider AB, at point A (arm angle rotates around point C), from point B to create a circle 2 (g pictured), AG
Divider BC, at point B, cut the circle 2, we get the point F
Ruler, line through the points A and F, AG
112.png
(edited 8 years ago)
PART THREE
Divider BF from point B, cuts line e is afforded point J
point G on circuit 1 (free choice),
ruler connect points A and G, we get along AG, we get the angle BAG
Divider GB, from the point B, we cut a circle 1, we get the point I
Divider GB, from the point I, we cut a circle1, we get the point H
Ruler join the dots G and J, we get along GJ
Ruler join the dots H and J, we get along JH, we get the angle GJH
angle GAB = angle GJH
Ruler merge point B and J, JB get along, we get the angle GJB
Ruler merge points I and J, we get along IJ, BJI get the angle, we get the angle IJH
ladies and gentlemen looking for a mistake ...
3.png
Divider BF from point B, cuts line e is afforded point J
point G on circuit 1 (free choice),
ruler connect points A and G, we get along AG, we get the angle BAG
Divider GB, from the point B, we cut a circle 1, we get the point I
Divider GB, from the point I, we cut a circle1, we get the point H
Ruler join the dots G and J, we get along GJ
Ruler join the dots H and J, we get along JH, we get the angle GJH
angle GAB = angle GJH
Ruler merge point B and J, JB get along, we get the angle GJB
Ruler merge points I and J, we get along IJ, BJI get the angle, we get the angle IJH
ladies and gentlemen looking for a mistake ...
3.png
I found how to determine the proportion of angles, and thus solve the trisection angles
Given the angle CAB
Divider AD (Point D is the free choice of the branch AB), from point A, creates a circular arc ED
Bisection circular arc ED obtained item H
Divider AD, from point D, obtained point L
Divider AD, from the point of L, we get the point F
Divider AF, from point A, creates a circular arc FG
Divider DH, from the point F, intersects a circular arc FG, obtained point I
Divider DH, referred to in Clause, cuts a circular arc FG, obtained point J
Divider FJ, from point J, cuts a circular arc FG, obtained point K
333.png
Next - my character- Solution of the construction of a regular n (n> 2) of the polygon
Given the angle CAB
Divider AD (Point D is the free choice of the branch AB), from point A, creates a circular arc ED
Bisection circular arc ED obtained item H
Divider AD, from point D, obtained point L
Divider AD, from the point of L, we get the point F
Divider AF, from point A, creates a circular arc FG
Divider DH, from the point F, intersects a circular arc FG, obtained point I
Divider DH, referred to in Clause, cuts a circular arc FG, obtained point J
Divider FJ, from point J, cuts a circular arc FG, obtained point K
333.png
Next - my character- Solution of the construction of a regular n (n> 2) of the polygon
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Posted from TSR Mobile
Posted from TSR Mobile
Original post by point.ms
Divider DH, referred to in Clause, cuts a circular arc FG, obtained point J
Divider DH, referred to in Clause, cuts a circular arc FG, obtained point J
should be - Divider DH, from the point I, intersects a circular arc FG, obtained point J
Original post by physicsmaths
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solution to the problem, to you to check the procedure with angles the other better methods to check whether the correct procedure ...
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