The Student Room Group

Differentiation C2

Find the greatest value of 6xx2 6x - x^2 State the range of the function f(x)=6xx2 f(x) = 6x - x^2

y=6xx2 y = 6x - x^2

f(x)=62x f'(x) = 6 - 2x

f(x)=0,x=3 f'(x) = 0, x = 3

y=18329 y = 18 - 3^2 - 9

So, the greatest value of this quadratic is 9, but how do I find the range of the function??
The range is the set of all second elements of ordered pairs (y-coordinates). As you know what the maximum y value is then it shouldn't be too hard to construct an inequality involving y or f(x).
Reply 2
Original post by keromedic
The range is the set of all second elements of ordered pairs (y-coordinates). As you know what the maximum y value is then it shouldn't be too hard to construct an inequality involving y or f(x).


English please
Reply 3
Original post by Psst.
English please


Capture.JPG

Above is the graph of f(x)=6xx2f(x) = 6x - x^2.
You know that the maximum is at y=9. What, then, can you say about the possible values of y? What can y be?
Reply 5
Original post by Psst.
Find the greatest value of 6xx2 6x - x^2 State the range of the function f(x)=6xx2 f(x) = 6x - x^2

y=6xx2 y = 6x - x^2

f(x)=62x f'(x) = 6 - 2x

f(x)=0,x=3 f'(x) = 0, x = 3

y=18329 y = 18 - 3^2 - 9

So, the greatest value of this quadratic is 9, but how do I find the range of the function??



sketch the graph
range is associated with y values.
Assuming the whole graph is there the range is y<=9
range = <f(x)9 -\infty < f(x) \leq 9
Reply 7
Original post by TeeEm
sketch the graph
range is associated with y values.
Assuming the whole graph is there the range is y<=9


Why can't y be greater than 9
Reply 8
Original post by Psst.
Why can't y be greater than 9


because the vertex of the graph is at (3,9) (highest point)
Reply 9
Original post by TeeEm
because the vertex of the graph is at (3,9) (highest point)


Just realised what's going on! Thanks Grandad :badger:
Original post by Psst.
Find the greatest value of 6xx2 6x - x^2 State the range of the function f(x)=6xx2 f(x) = 6x - x^2

y=6xx2 y = 6x - x^2

f(x)=62x f'(x) = 6 - 2x

f(x)=0,x=3 f'(x) = 0, x = 3

y=18329 y = 18 - 3^2 - 9

So, the greatest value of this quadratic is 9, but how do I find the range of the function??


I find it easy to sketch out the graph.
The range = what the y values can be.
In this case, your stationary point is y=9 and the curve is a upside down u.
So the y values are gonna stat at 9 and decrease
So y≤9

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