GCSE Chemistry: Quantitive chemistry question
If anyone could help me with this question it would be much appreciated
NaOH + HCl -> NaCl + H2O
A 25cm3 sample of NaOH (0.125mol/dm3) required 21.6cm3 of HCl for complete neutralisation
A) calculate the number of moles of NaOH neutralised by the hydrochloric acid
I got 2.7 moles
B) use the balanced equation to deduce the number of moles of hydrochloric acid in 21.6cm3
Is part b even in english
NaOH + HCl -> NaCl + H2O
A 25cm3 sample of NaOH (0.125mol/dm3) required 21.6cm3 of HCl for complete neutralisation
A) calculate the number of moles of NaOH neutralised by the hydrochloric acid
I got 2.7 moles
B) use the balanced equation to deduce the number of moles of hydrochloric acid in 21.6cm3
Is part b even in english
Original post by Jamiemcq
If anyone could help me with this question it would be much appreciated
NaOH + HCl -> NaCl + H2O
A 25cm3 sample of NaOH (0.125mol/dm3) required 21.6cm3 of HCl for complete neutralisation
A) calculate the number of moles of NaOH neutralised by the hydrochloric acid
I got 2.7 moles
NaOH + HCl -> NaCl + H2O
A 25cm3 sample of NaOH (0.125mol/dm3) required 21.6cm3 of HCl for complete neutralisation
A) calculate the number of moles of NaOH neutralised by the hydrochloric acid
I got 2.7 moles
incorrect
Moles = molarity x volume(in litres)
Original post by charco
incorrect
Moles = molarity x volume(in litres)
Moles = molarity x volume(in litres)
Molarity?
Ive learnt it as
No. Of moles = concentration × volume
Original post by Jamiemcq
Molarity?
Ive learnt it as
No. Of moles = concentration × volume
Ive learnt it as
No. Of moles = concentration × volume
molarity = concentration in moles per litre
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