Edexcel S1 - 15th June, 2016 [Exam Discussion]

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Original post by Pink1998

Hi, for last year's June 2015 paper. In the last question they've written P(X>w / X>28)
Is that "/" a divide sign or a "given that" sign?
Thank you

given that.
same applies to standard probability qs

Reply 581

Guèpard

Original post by jackf9283

if you have boundaries of 0-4 is the class width of that data 4.5 or 5 as the upper bound would be 4.5 assuming the next boundary if 5-something. But would you use -0.5 or just 0

Im guessing it would be 0, depends on the context of the question for example you cant drive negative 0.5 miles something like that hope it helps :smile:

Reply 582

SweetChilliCake

Original post by MMMSS

were you able to find the regression line in terms of and b?

y=0.746+0.102x

Reply 583

siamesedaffodil

Using a venn diagram..

...how would you work out P(A' U B) and P(A' U B')?? ? ?

Thanks!!

Reply 584

Jack_Linaker

Original post by AlphaWolfZ

Mega Thanks buddy. Why do you divide one over the other? Is that the rule?

The rule is P(B|A) = P(AnB)/P(A) so it's the probability of both events divided by the given event. For example in the phone charger question, for both events to occur it has to be greater than 133. Do you see what I mean?

Reply 585

NigelK98

Original post by Guèpard

ExamSolutions is playing up!

Seriously, now had to be the time :colonhash:

yh so tru i thought it was my internet connection being slow

Reply 586

Jack_Linaker

Original post by Guèpard

ExamSolutions is playing up!

Seriously, now had to be the time :colonhash:

Normally happens the night before an exam, the website gets a lot of traffic.

Reply 587

AlphaWolfZ

Original post by Jack_Linaker

Slightly. How do we work out P(AnB)?

Reply 588

MMMSS

Original post by SweetChilliCake

y=0.746+0.102x

Ok so it's a matter of substitution- youve been given the codes for x and y

so instead of y=0.746+0.102x,
you will now get v/100,000 = 0.746 + 0.102*(s-50/10)

then simplify:
v= 23600 + 1020 s

ergo, d= 1020

Reply 589

Jack_Linaker

Original post by AlphaWolfZ

Slightly. How do we work out P(AnB)?

That's the probability of both events occurring, A and B. In the case of the phone charger question you work it out the same way you worked out P(L>127) in part a.

Reply 590

hiiiiiiiiiiii

does anyone know the grade boundaries for the 2016 IAL S1 paper?

Reply 591

studentsixth

When you draw a regression line, does it go through the mean point?

Reply 592

Exavior

Original post by siamesedaffodil

Using a venn diagram..

...how would you work out P(A' U B) and P(A' U B' :wink:

?? ? ?

Thanks!!

P(A'UB) would be everything except P(A)-P(AnB) so just everything but the bit where A doesnt overlap with B including the outside area.
P(A'UB') would be the outside area

Reply 593

Exavior

Original post by studentsixth

When you draw a regression line, does it go through the mean point?

Yes it should

Reply 594

Econmaster

This only means that it is not A and is B which means that it is all the probabilities that cover that area

Reply 595

Jack_Linaker

Original post by studentsixth

When you draw a regression line, does it go through the mean point?

I'm pretty sure, yeah.

Reply 596

Najmac

how you all feeling for tomorrow?/

Reply 597

Bigbosshead

Original post by Exavior

P(A'UB) would be everything except P(A)-P(AnB) so just everything but the bit where A doesnt overlap with B including the outside area.
P(A'UB' :wink:

would be the outside area

P(A'UB') is everything apart from P(A intersection B)