0.1 x 0.2 = 0.02 moles of NaCl. Therefore, there are 0.02 moles of Na+ in the NaCl 0.1 x 0.2 = 0.02 moles of Na2C03. Therefore, there are 0.02 moles of Na2 in the Na2CO3 meaning there are 0.04 moles of Na+ in Na2CO3. 0.02 + 0.04 = 0.06 moles The total volume is 200cm3. 0.06/ 0.02dm3 = 0.3mol/dm3