C3 edexcel chp6 ex 6e q5 help!!!
does anyone get the question and understand the solution... please help
sin x = k , so take the inverse , so that x = arcsin k , but arcsin k = , so one solution is . Now find the other positive solution using a quadrant diagram or graph to help.
Original post by NotNotBatman
sin x = k , so take the inverse , so that x = arcsin k , but arcsin k = , so one solution is . Now find the other positive solution using a quadrant diagram or graph to help.
sin x = k , so take the inverse , so that x = arcsin k , but arcsin k = , so one solution is . Now find the other positive solution using a quadrant diagram or graph to help.
ohhh ok, i understand how to get the 1st solution but i don't get why the 2nd solution is pi - alpha
Because it is in the 1st quadrant between 0 and pi/2
(edited 7 years ago)
Original post by ilovemaths2017
ohhh ok, i understand how to get the 1st solution but i don't get why the 2nd solution is pi - alpha
Since k is positive then arcsin k is positive, so alpha is positive and alpha must be less than 1, so the other positive solution is pi - aplha.
Think about the quadrant diagram or the sine graph if you prefer, when working out the solution to x = arcsin(constant), another solution is pi - principal solution.
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