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Square numbers and division

why does dividing a squared number (say 4 squared) by a number (say 2) equal the same as dividing 4 by 2 then times by the remaining 4
So the first one is n22\frac{n^2}{2}

n2×n=n2×n1 \frac{n}{2} \times n = \frac{n}{2} \times \frac{n}{1} when you multiply a fraction, you multiply through the top and bottom, so (n2×n1)=n×n2×1=n22(\frac{n}{2} \times \frac{n}{1}) = \frac{n \times n}{2 \times 1} = \frac{n^2}{2} It doesn't matter which way round you multiply and divide, the result will be the same.
Reply 2
Original post by NotNotBatman
So the first one is n22\frac{n^2}{2}

n2×n=n2×n1 \frac{n}{2} \times n = \frac{n}{2} \times \frac{n}{1} when you multiply a fraction, you multiply through the top and bottom, so (n2×n1)=n×n2×1=n22(\frac{n}{2} \times \frac{n}{1}) = \frac{n \times n}{2 \times 1} = \frac{n^2}{2} It doesn't matter which way round you multiply and divide, the result will be the same.


Thank you so much this has been very helpful!

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