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Maths further pure 2

Question 5a on this paper;
http://pmt.physicsandmathstutor.com/download/Maths/A-level/FP2/Papers-Edexcel/June%202014%20(IAL)%20MA%20-%20F2%20Edexcel.pdf
Why can you go from 2x(dy^3/dx^3) to 2x(2xdy^2/dx^2)?
Thanks
(edited 5 years ago)
Original post by examstudy
Question 5a on this paper;
http://pmt.physicsandmathstutor.com/download/Maths/A-level/FP2/Papers-Edexcel/June%202014%20(IAL)%20MA%20-%20F2%20Edexcel.pdf
Why can you go from 2x(dy^3/dx^3) to 2x(2xdy^2/dx^2)?
Thanks


First line. The two things cancel so you can move the 2xd2ydx22x \dfrac{d^2 y}{dx^2} term to the right hence obtain the equality you're asking about.
Reply 2
Thank you for replying,
I am talking about the end of the second line on the MS.
Where it is put into the correct form I dont understand how they go from the third order differentiation back to a second order one?





Original post by RDKGames
First line. The two things cancel so you can move the 2xd2ydx22x \dfrac{d^2 y}{dx^2} term to the right hence obtain the equality you're asking about.
Original post by examstudy
Thank you for replying,
I am talking about the end of the second line on the MS.
Where it is put into the correct form I dont understand how they go from the third order differentiation back to a second order one?


They replace d3ydx3\dfrac{d^3 y}{dx^3} by 2xd2ydx22x\dfrac{d^2 y}{dx^2} since we have shown that they're equal!
Reply 4
Original post by RDKGames
They replace d3ydx3\dfrac{d^3 y}{dx^3} by 2xd2ydx22x\dfrac{d^2 y}{dx^2} since we have shown that they're equal!


Ohhhhhh!
I understand thank you!!!

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