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Edexcel Heinemann M3 HELP

david cool

further dynamics
page 75
question 14

ITS ON shm i NEED some help dont get it !

Reply 1

Fermat

You couldn't post the question, could you?

Reply 2

Gaz031

Fermat

You couldn't post the question, could you?

I guess he can't but despite the fact i'm not on that yet i can:
P75, Q14:
Points A, O, B lie in that order along a straight line. A particle P is moving on the line with S.H.M of period 3seconds, amplitude 0.6m and centre O. Given that OA is 0.3m and OB is 0.4m, calculate the time taken by P to move directly from A to B.

Answer: 0.598 seconds.

Reply 3

Fermat

x = Asin(wt + ø) w = 2pi/T

setting ø = 0 & w = 2pi/3
x = 0.6sin(2pi.t/3)

Time to displace by 0.3m from origin is given by,

0.3 = 0.6sin(2pi/3)
sin(2pi.t/3) = 0.3/0.6 = ½
2pi.t/3 = pi/6
t1 = ¼s
======

Time to displace by 0.4m from origin is given by,

0.4 = 0.6sin(2pi.t/3)
sin(2pi.t/3) = 0.2/0.6 = 2/3
2pi.t/3 = 0.729 rad
t2 = 0.348s
========

Sum of displacement times is,

t = t1+t2 = 0.25 + 0.348
t = 0.598s
=======

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