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How do you do anti log on the calculator!

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    This was really annoying me, plus the fact that none of my teachers told me how to do it! But what exactly do you press on the calculator. For example:
    An acid has a pH of 3. What is the concentartion of H+ ions?
    pH=-log10[H+]
    3=-log10[H+]
    -3=log10[H+]

    The answer is [H+] = 10-3 moldm-3.

    errr my question is how?:confused:
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    Err....that's right...

    In general your antilog function should be "shift/2nd function" and then the log button

    or if you really cant find it, just do

     10^-^p^H
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    10^
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    wtf is anti-log?

    If I have to calculate the concenrtation of H+ ions, I go:

    -3 = log (base 10) (H+)
    which is equal to:
    10^-3=H+
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    Anti-log is the inverse of the log function, antilog is also known as 10^. It works the same as e^ is the inverse of the ln function.
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    (Original post by IChem)
    Err....that's right...

    In general your antilog function should be "shift/2nd function" and then the log button

    or if you really cant find it, just do

     10^-^p^H
    THANK YOU!!!!!! OH I COULD JUST KISS YOU! YOU DON'T UNDERSTAND FOR HOW LONG I WAS TRYING TO WORK THAT OUT FOR!
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    Hehe, damn I'm good :p:
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    (Original post by IChem)
    Hehe, damn I'm good :p:
    Pfft, editing after I posted the answer :hmmm:

    :p:
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    Meh, I knew it anyway, I just added on a little extra to my post...
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    (Original post by IChem)
    Meh, I knew it anyway, I just added on a little extra to my post...
    PLAYJEEARISM!!?!?!1

    I think I've made my point.

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    No-one has given a precise answer - it depends on the base. Log(base 2)y = x is "anti-logged" by raising 2^x. lny = x is "anti-logged" by raising e^x.

    However, the standard on the calculator uses base 10 so I'll let you off... for now.
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    (Original post by HCD)
    No-one has given a precise answer - it depends on the base. Log(base 2)y = x is "anti-logged" by raising 2^x. lny = x is "anti-logged" by raising e^x.

    However, the standard on the calculator uses base 10 so I'll let you off... for now.
    However, adapted to these circumstances (calculations involving pH) it will be nothing but log (base 10) :p:

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