d = 1/N = 1/(400x10^3)
use dsinθ=nλ
sin θ = 2 x 500 x 10^-9 x 400 x 10^3
There are 2 second order maxima, one on each side of the zero order central maximum.
The angle required is therefore 2 θ = 47.2 degrees
use dsinθ=nλ
sin θ = 2 x 500 x 10^-9 x 400 x 10^3
There are 2 second order maxima, one on each side of the zero order central maximum.
The angle required is therefore 2 θ = 47.2 degrees
Original post by BobbJo
d = 1/N = 1/(400x10^3)
use dsinθ=nλ
sin θ = 2 x 500 x 10^-9 x 400 x 10^3
There are 2 second order maxima, one on each side of the zero order central maximum.
The angle required is therefore 2 θ = 47.2 degrees
use dsinθ=nλ
sin θ = 2 x 500 x 10^-9 x 400 x 10^3
There are 2 second order maxima, one on each side of the zero order central maximum.
The angle required is therefore 2 θ = 47.2 degrees
Great, thank you so much
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