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Physics question circular motion

Hi, please could i have help on this question? I’ve attached my working out below and I’m pretty sure the markscheme is wrong because surely the tan theta should be equal to the weight divided by centripetal force? The markscheme says the answer is 36 degrees.
Here is the question: https://app.gemoo.com/share/image-annotation/615280820973907968?codeId=Paj0AnQQR8OO5&origin=imageurlgenerator


Here is my attempt: https://app.gemoo.com/share/image-annotation/615280242726154240?codeId=vzxAVB6553Ar0&origin=imageurlgenerator

Thank you!
Original post by anonymous294
Hi, please could i have help on this question? I’ve attached my working out below and I’m pretty sure the markscheme is wrong because surely the tan theta should be equal to the weight divided by centripetal force? The markscheme says the answer is 36 degrees.
Here is the question: https://app.gemoo.com/share/image-annotation/615280820973907968?codeId=Paj0AnQQR8OO5&origin=imageurlgenerator


Here is my attempt: https://app.gemoo.com/share/image-annotation/615280242726154240?codeId=vzxAVB6553Ar0&origin=imageurlgenerator

Thank you!


I would recommend that you draw your free-body diagram clearly and you would see why you are incorrect.
Reply 2
Original post by Eimmanuel
I would recommend that you draw your free-body diagram clearly and you would see why you are incorrect.

I tried drawing it again but I don’t see where I’m going wrong, I’ve drawn weight vertically and lift perpendicular to the wings of the airplane so i then resolve weight into its vertical and horizontal components with the vertical part balancing weight and the horizontal part being the centripetal force?
Original post by anonymous294
I tried drawing it again but I don’t see where I’m going wrong, I’ve drawn weight vertically and lift perpendicular to the wings of the airplane so i then resolve weight into its vertical and horizontal components with the vertical part balancing weight and the horizontal part being the centripetal force?

Weight is already in the vertical direction, so I don't understand why you resolve weight into its vertical and horizontal components.
It would be better that show your diagram of free-body diagram.
Reply 4
Original post by anonymous294
I tried drawing it again but I don’t see where I’m going wrong, I’ve drawn weight vertically and lift perpendicular to the wings of the airplane so i then resolve weight into its vertical and horizontal components with the vertical part balancing weight and the horizontal part being the centripetal force?

Weight has no horizontal componemt.

Your diagrams need to be bigger - just draw the plane simply
Reply 5
Original post by Eimmanuel
Weight is already in the vertical direction, so I don't understand why you resolve weight into its vertical and horizontal components.
It would be better that show your diagram of free-body diagram.

Sorry i meant i resolved lift into vertical and horizontal components, but is the angle drawn on the diagram the angle to the horizontal? Surely its the angle in red https://app.gemoo.com/share/image-annotation/615313467284541440?codeId=DGa2qKRdBKAQ7&origin=imageurlgenerator
(edited 2 months ago)
Original post by anonymous294
Sorry i meant i resolved lift into vertical and horizontal components, but is the angle drawn on the diagram the angle to the horizontal? Surely its the angle in red https://app.gemoo.com/share/image-annotation/615313467284541440?codeId=DGa2qKRdBKAQ7&origin=imageurlgenerator


I disagree with “Surely, its angle in red”.
The angle that the aeroplane makes with the horizontal is NOT the angle you have drawn in red, it is the angle theta that is drawn in the diagram.
Take the horizontal component of the lift force shown in the diagram as the reference horizontal line. This horizontal line makes an angle with the wings, which is the angle the question is asking.
Using some geometry arguments, you can show that it is the angle theta shown in the diagram.
Reply 7
Original post by Eimmanuel
I disagree with “Surely, its angle in red”.
The angle that the aeroplane makes with the horizontal is NOT the angle you have drawn in red, it is the angle theta that is drawn in the diagram.
Take the horizontal component of the lift force shown in the diagram as the reference horizontal line. This horizontal line makes an angle with the wings, which is the angle the question is asking.
Using some geometry arguments, you can show that it is the angle theta shown in the diagram.

Ok thank you!

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