mechanics projectiles

shreya_2003

i used this for T=2Usintheta/g
and
s=s
u=Usintheta
v=x
a=-g
t=2Usintheta/g and cant seem to get the answer.

Workings
(Usintheta x 2Usintheta)/g - g x 1/2 x (2Usintheta/g)^2
cancelled out to get
U^2 sin^2theta x (-2U^2 Sin^2theta/g)

(edited 2 years ago)

Original post by shreya_2003

i used this for T=2Usintheta/g
and
s=s
u=Usintheta
v=x
a=-g
t=2Usintheta/g and cant seem to get the answer.

Workings
(Usintheta x 2Usintheta)/g - g x 1/2 x (2Usintheta/g)^2
cancelled out to get
U^2 sin^2theta x (-2U^2 Sin^2theta/g)

OA is the horizontal distance. So youve worked out the time, sub it into the horizontal motion.
The sin(2theta) is a hint as it involves both sin(theta) and cos(theta) so you must be combining both horizontal and vertical motion.

Reply 2

shreya_2003

OP

11

Original post by mqb2766

OA is the horizontal distance. So youve worked out the time, sub it into the horizontal motion.
The sin(2theta) is a hint as it involves both sin(theta) and cos(theta) so you must be combining both horizontal and vertical m