inductor current (HNC maths)

The current (𝑖𝐿) through a 100 mH inductor (L) has a relationship with time (t) as follows:
𝑖𝐿 = 1/L ∫ cos(300𝑡) 𝑑t
Determine the inductor current when the time is 0.75 seconds.

ive managed to integrate this equation fine to
i_l = (1/L) (1/300) sin(300t) + C
however i know now i can input the values for L and t however im unsure how to calculate the constant C

Reply 1

mqb2766

21

Original post by Jeffers999

The current (𝑖𝐿) through a 100 mH inductor (L) has a relationship with time (t) as follows:
𝑖𝐿 = 1/L ∫ cos(300𝑡) 𝑑t
Determine the inductor current when the time is 0.75 seconds.

ive managed to integrate this equation fine to
i_l = (1/L) (1/300) sin(300t) + C
however i know now i can input the values for L and t however im unsure how to calculate the constant C

The cos() in the original question must represent the instantaneous voltage across the resistor and Im presuming its "switched on" at t=0 when the current is zero.

Reply 2

Jeffers999

OP

6

Original post by mqb2766

The cos() in the original question must represent the instantaneous voltage across the resistor and Im presuming its "switched on" at t=0 when the current is zero.

Yea ive gotten to that aswell ,
Im pretty sure my integration is correct im just confused and what to do with the C constant at the end as i dont know how to work out value for it in this case

Reply 3

mqb2766

21

Original post by Jeffers999

Yea ive gotten to that aswell ,
Im pretty sure my integration is correct im just confused and what to do with the C constant at the end as i dont know how to work out value for it in this case