The Student Room Group
Reply 1
Anyone? Sorry, I'm in a bit of a rush :frown:
My result isn't the same as yours for the first one: rewrite the right-hand side as A2+1A\dfrac{A^2+1}{A} and it becomes easily separable.

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Reply 3
Glutamic Acid
My result isn't the same as yours for the first one: rewrite the right-hand side as A2+1A\dfrac{A^2+1}{A} and it becomes easily separable.

Spoiler


Thanks :smile:

Also, any ideas for the other 2?
jobo3
Thanks :smile:

Also, any ideas for the other 2?


The second is also just separation of variables. Divide through by tan(theta) and r, and 'multiply' through by dr. Integrate both sides.

For the third, just 'multiply' through by dv and integrate both sides...
Reply 5
:frown: I thought these were harder than they were, I've been trying to get them in the general form and find the integrating factor etc .. :getmecoat:
Second one: write tan theta = sin theta / cos theta, then separate variables to get cosθsinθdθ=1rdr\displaystyle \int \frac{\cos \theta}{\sin \theta} \, \text{d}\theta = \displaystyle \int \frac{1}{r} \, \text{d}r. LHS = a function and its derivative...

Third one: It's already separable, and to integrate the RHS write 1/v^(1/2) as v^(-1/2).
Reply 7
Yep thanks a lot :yy: done them all now :smile:

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