A free electron is described by the wave function, .ψ (x)=Ae^i2pi/lamba x Using the

Does anyone know how I can answer this question?

A free electron is described by the wave function, .ψ (x)=Ae^i2pi/lamba x Using the linear momentum operator, p = -iħ d/dx, derive an expression for the momentum of the electron. Is your answer consistent with de Broglie's equation?

(edited 6 months ago)

Reply 1

mqb2766

21

Original post by constatinetwell

Does anyone know how I can answer this question?

A free electron is described by the wave function, .ψ (x)=Ae^i2pi/psi x Using the linear momentum operator, p = -iħ d/dx, derive an expression for the momentum of the electron. Is your answer consistent with de Broglie's equation?

Can you post an image of the question, and if Ive understood the wave function correctly, what is hte problem with simply differentiating it

(edited 6 months ago)

Reply 2

thegoldenkimpa

6

yeah its just differentiating

Reply 3

mqb2766

21

Original post by thegoldenkimpa

yeah its just differentiating
...

Its best just to give a hint and let the OP do as much as possible themselves.

Reply 4

RichE

15

Original post by constatinetwell

Does anyone know how I can answer this question?

A free electron is described by the wave function, .ψ (x)=Ae^i2pi/psi x Using the linear momentum operator, p = -iħ d/dx, derive an expression for the momentum of the electron. Is your answer consistent with de Broglie's equation?