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NSAA Chemistry help

''an aluminium wire is put into a beaker with 1000ml solution of pb(no3)2. after the total precipitation of Pb, the wire's mass has changed by 56.7g .
What was the initial concentration of the solution? ''
I know it's a displacement reaction with equation: 2Al + 3Pb(NO3)2 --> 3Pb + 2Al(NO3)3, but I'm not sure how to relate the change in mass to the molar ratios.
Original post by ambot
''an aluminium wire is put into a beaker with 1000ml solution of pb(no3)2. after the total precipitation of Pb, the wire's mass has changed by 56.7g .
What was the initial concentration of the solution? ''
I know it's a displacement reaction with equation: 2Al + 3Pb(NO3)2 --> 3Pb + 2Al(NO3)3, but I'm not sure how to relate the change in mass to the molar ratios.

The wire has lost 56.7g so 56.7g of Al reacted.
So find the moles of Al using n = mass/mr
Use mole ratio
Find moles of Pb(NO3)2
Use c = n/v
Reply 2
Original post by BankaiGintoki
The wire has lost 56.7g so 56.7g of Al reacted.
So find the moles of Al using n = mass/mr
Use mole ratio
Find moles of Pb(NO3)2
Use c = n/v

ahhh thank you so much -
mol Al reacted = 56.7/27 = 2.1
Moles ratio of Al to Pb2+ is 2:3 so moles of Pb = (2.1/2) x 3 = 3.15mol.
conc.(Pb(NO3)2) = 3.15mol/1dm3 = 3.15M.

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