Youve missed the (x) next to the sin and cos hence the confusion in the reply. Your numbers are about right, though there are a couple of sign errors (and the tan(x) value doesnt follow from your numbers) and it generally helps to make the coeffs as positive as possible. Post your working if you cant get it sorted.

(edited 3 months ago)

Reply 5

Can'tDecideAName

2sin(x-60)=cos(x-30) you are trying to find a solution to this equation in terms of tan(x) correct?

If so then you can just use the compound angle formulae (sin(A+B) = sin(A)cos(B) + cos(A)sin(B) & cos(A+B) = cos(A)cos(B) - sin(A)sin(B))

This would give you:
sin(x) - √3 cos(x) = √3/2 cos(x) + 1/2 sin(x)

You should be able to rearrange that to get an equation relating tan(x) to a number

(edited 3 months ago)

Reply 6

mqb2766

Original post by Can'tDecideAName

2sin(x-60)=cos(x-30) you are trying to find a solution to this equation in terms of tan(x) correct?

If so then you can just use the compound angle formulae (sin(A+B) = sin(A)cos(B) + cos(A)sin(B) & cos(A+B) = cos(A)cos(B) - sin(A)sin(B))

This would give you:
sin(x) - √3/4 cos(x) = √3/2 cos(x) + 1/2 sin(x)

You should be able to rearrange that to get an equation relating tan(x) to a number

Looks like there is a typo in your expansion,

Reply 7

Can'tDecideAName

Original post by mqb2766

Looks like there is a typo in your expansion,

Hahahaha, my apologies 😁

It's no typo, I've mistakenly used a factor of 1/2 instead of 2 giving √3/4 instead of √3

Thank you for the correction, it has been fixed :smile: