Help needed!

danmint

does anyone know how to differenciate sec^n-1 x?

Any help would be much appreciated thanks!

Reply 1

Gaz031

danmint

does anyone know how to differenciate sec^n-1 x?

Any help would be much appreciated thanks!

Use the chain rule to get (n-1)sec^(n-2)x.secxtanx = (n-1)sec^(n-1)xtanx.

Edit: I missed the '^' power symbol off. Does that clarify things?

Reply 2

danmint

Gaz031

Use the chain rule to get (n-1)sec^(n-2)x.secxtanx = (n-1)sec(n-1)xtanx.

thank you very much for the help! although i only got (n-1) and not (n-1)^2? on the end answer, maybe you've spelt it wrong but i got:

du/dx sec^n-1 x = (n-1)sec^n x tanx?

ah wait a sec! yup your right , i see where i made my mistake! thanks very muccch!

Reply 3

danmint

ok guys i know im going to sound really stupid but does anyone know the integral of secx?

Reply 4

dvs

ln|secx+tanx| or ln|tan(x/2) + pi/4|.

You can get the first one by multiplying secx by (secx+tanx)/(secx+tanx) then noting that the nominator becomes the derivative of the denominator, and you can get the second one using the substituion t=tan(x/2).

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