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determining the structure of a compound using spectra part 3 (only 1 hour left!)
molecular formula C4H10O
molecular ion 74
zero degree of unsaturation
IR read 3400 and 1100 suggesting alcohol
NMR has 3 environments
spec data attached
graphs linked
http://www.filefactory.com/file/af61582/n/93_NMR_pdf
http://www.filefactory.com/file/af6158e/n/93_IR_pdf
ive got another 2 to do aswell before 4
molecular ion 74
zero degree of unsaturation
IR read 3400 and 1100 suggesting alcohol
NMR has 3 environments
spec data attached
graphs linked
http://www.filefactory.com/file/af61582/n/93_NMR_pdf
http://www.filefactory.com/file/af6158e/n/93_IR_pdf
ive got another 2 to do aswell before 4
Well for a start there is no oxygen in the elemental analysis
C: 94.3
H: 5.7
------
100%
C: 94.3
H: 5.7
------
100%
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Im confused about this chemistry question, why does it form these productsTrending
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Im confused about this chemistry question, why does it form these products
