The Student Room Group

SN1 and SN2 reactions (chemistry)

Hello everyone,

I'm having trouble understanding the reactivity of halogenoalkanes in nucleophilic substitution reactions.

Can someone explain why primary halogenoalkanes undergo SN2 reactions, while tertiary halogenoalkanes preferentially undergo SN1 reactions? Also, are there any exceptions to these trends? Thanks in advance.
Halogenoalkanes are organic compounds containing a halogen atom connected to an alkyl group. In nucleophilic substitution reactions, these compounds react with a nucleophile (a species with an electron-rich atom, such as a negatively charged ion) to form a new chemical compound.

Primary halogenoalkanes, which contain a single carbon-halogen bond, undergo SN2 substitution reactions. This is because these compounds have a relatively weak carbon-halogen bond. The electron-rich nucleophile is able to attack the carbon atom and form a new bond, resulting in the substitution of the halogen atom.

Tertiary halogenoalkanes, which contain three carbon-halogen bonds, are much more likely to undergo SN1 substitution reactions. This is because the carbon-halogen bonds in these compounds are stronger, making it difficult for the nucleophile to attack the carbon atom. Instead, the carbon-halogen bond breaks, forming a carbocation intermediate. The nucleophile then attacks the carbocation, resulting in the substitution of the halogen atom.

There are some exceptions to these general trends. For example, secondary halogenoalkanes can undergo both SN2 and SN1 reactions depending on the reaction conditions and the type of nucleophile used. Additionally, if the reaction conditions or nucleophile are particularly favorable, a primary halogenoalkane may undergo an SN1 reaction.


Regards Jaydenmaster42
Original post by jaydenmaster
Halogenoalkanes are organic compounds containing a halogen atom connected to an alkyl group. In nucleophilic substitution reactions, these compounds react with a nucleophile (a species with an electron-rich atom, such as a negatively charged ion) to form a new chemical compound.

Primary halogenoalkanes, which contain a single carbon-halogen bond, undergo SN2 substitution reactions. This is because these compounds have a relatively weak carbon-halogen bond. The electron-rich nucleophile is able to attack the carbon atom and form a new bond, resulting in the substitution of the halogen atom.

Tertiary halogenoalkanes, which contain three carbon-halogen bonds, are much more likely to undergo SN1 substitution reactions. This is because the carbon-halogen bonds in these compounds are stronger, making it difficult for the nucleophile to attack the carbon atom. Instead, the carbon-halogen bond breaks, forming a carbocation intermediate. The nucleophile then attacks the carbocation, resulting in the substitution of the halogen atom.

There are some exceptions to these general trends. For example, secondary halogenoalkanes can undergo both SN2 and SN1 reactions depending on the reaction conditions and the type of nucleophile used. Additionally, if the reaction conditions or nucleophile are particularly favorable, a primary halogenoalkane may undergo an SN1 reaction.


Regards Jaydenmaster42


Mostly correct.

You don’t classify halogenoalkanes as 1°, and based on how many carbon-halogen bonds there are: you instead classify them based on how many carbons are bound to the carbon on which the halogen is itself bound.

The effect of the classification of the halogenoalkane on which mechanism the reaction follows is more to do with the steric bulk of the surrounding alkyl groups than it is to do with bond strength.

By any chance, was this a ChatGPT response?
Original post by TypicalNerd
Mostly correct.

You don’t classify halogenoalkanes as 1°, and based on how many carbon-halogen bonds there are: you instead classify them based on how many carbons are bound to the carbon on which the halogen is itself bound.

The effect of the classification of the halogenoalkane on which mechanism the reaction follows is more to do with the steric bulk of the surrounding alkyl groups than it is to do with bond strength.

By any chance, was this a ChatGPT response?

Not really, am also learning, have noted your insight on classification of halogenoalkanes and their reaction
Original post by jaydenmaster
Not really, am also learning, have noted your insight on classification of halogenoalkanes and their reaction


Fair enough.

This resource may help: https://www.chemguide.co.uk/mechanisms/nucsub/hydroxidett.html
Reply 5
Original post by nheap
Hello everyone,

I'm having trouble understanding the reactivity of halogenoalkanes in nucleophilic substitution reactions.

Can someone explain why primary halogenoalkanes undergo SN2 reactions, while tertiary halogenoalkanes preferentially undergo SN1 reactions? Also, are there any exceptions to these trends? Thanks in advance.

SN1: there are two steps in the mechanism the rate determining step is unimolecular i.e. the leaving group (halide in this case) leaves (slow; rate determining step), then the nucleophile attacks at the carbocation (positive charge on the C). Remember that a nucleophile donates a pair of electrons (electrons are negatively charged).
For tertiary halogenoalkanes, the intermediate formed (once the halide has left) is a tertiary carbocation, which is far more stable than a primary carbocation which would theoretically be formed after the halide has left a primary halogenoalkane this is due to there being more alkyl groups attached to the C in the tertiary case, which means that the charge can spread around a bit more and so the tertiary carbocation is more stable.
https://www.chemguide.co.uk/mechanisms/eladd/carbonium.html
A primary carbocation is pretty unstable, so SN1 is not really favourable. Instead, the nucleophilic substitution occurs in just one step the C–X bond breaks at the same time as the C–Nu bond forms (SN2 bimolecular rate determining step the slow step involves two molecules). The carbon "centre" in a tertiary halogenoalkane is too crowded for this to happen alkyl groups are pretty big (much larger than the hydrogens in a primary halogenoalkane) so there isn't really much of a space where the nucleophile can attack.
https://www.chemguide.co.uk/mechanisms/nucsubmenu.html
Reply 6
Many thanks to TypicalNerd, bl0bf1sh and jaydenmaster for your replies. Thanks for the resources you have linked.

I did know about the relative stability of tertiary halogenoalkanes, but could not relate it to why only SN2 is possible.

"The carbon "centre" in a tertiary halogenoalkane is too crowded for this to happen alkyl groups are pretty big (much larger than the hydrogens in a primary halogenoalkane) so there isn't really much of a space where the nucleophile can attack."

Amazing explanations from all of you.

Thanks

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