As the car passes X the freq decreases because the wavefronts move away from each other and wavelength increases
But in actual sense if you think about it, as the car passes the point X where the observer was, frequency is meant to be increasing apparently due to compression of the wavefronts thus reduced wavelength... at first frequency was virtually zero since gradient was zero and the line was horizontal, then gradient increases and that's the point where it passes X then afterwards it becomes horizontal again as the wavefronts are now stretched hence no virtual increase in frequency
But in actual sense if you think about it, as the car passes the point X where the observer was, frequency is meant to be increasing apparently due to compression of the wavefronts thus reduced wavelength... at first frequency was virtually zero since gradient was zero and the line was horizontal, then gradient increases and that's the point where it passes X then afterwards it becomes horizontal again as the wavefronts are now stretched hence no virtual increase in frequency
Lol wtf are you talkin about ? :P Freq was on y axis and time was on x axis. So gradient of the graph would be something else,not freq. Freq was on y axis and it decreased as the car passed X, however there was no increase in freq and that made me a bit doubtful :V
Lol wtf are you talkin about ? :P Freq was on y axis and time was on x axis. So gradient of the graph would be something else,not freq. Freq was on y axis and it decreased as the car passed X, however there was no increase in freq and that made me a bit doubtful :V
The point X was in between the "falling frequency" part so right before passing X how on earth can the frequncy decrease?
Lol wtf are you talkin about ? :P Freq was on y axis and time was on x axis. So gradient of the graph would be something else,not freq. Freq was on y axis and it decreased as the car passed X, however there was no increase in freq and that made me a bit doubtful :V
Im aware that frequency was on the Y-axis, but there's no way on earth the frequency is reducing as the car moves towards you.. therefore the rate of change in frequency suddenly increases before remaining constant again indicating compression of the wavefronts.. I confirmed with my physics teacher as well
It was strange though, the frequency should've have been increasing right before the point X as the car moves towards you, whereas on the graph it was just a horizontal line. The frequency dropped at X and became horizontal again.
It was strange though, the frequency should've have been increasing right before the point X as the car moves towards you, whereas on the graph it was just a horizontal line. The frequency dropped at X and became horizontal again.
When it is horizontal, its almost like no frequency since its constant ( its like constant velocity= no acceleration eventhough the constant velocity can be high) that's how I reasoned
When it is horizontal, its almost like no frequency since its constant ( its like constant velocity= no acceleration eventhough the constant velocity can be high) that's how I reasoned
Yes, but that's not how doppler effect works, the closer a source gets to you, the less the distance between successive wavelengths when they reach you.
Yes, but that's not how doppler effect works, the closer a source gets to you, the less the distance between successive wavelengths when they reach you.
Exactly and so higher frequency, that's what I said.. in the graph it looked kinda weird but I mostly explained using my own knowledge about doppler
It was strange though, the frequency should've have been increasing right before the point X as the car moves towards you, whereas on the graph it was just a horizontal line. The frequency dropped at X and became horizontal again.
In the question it says after point x the car starts to move, before point x it was standing still so frequency will be constant.
What I think is that it was just meant to show higher frequency and lower frequency but then again why would it decrease if the car hasnt passed the spectator yet...... edexcel pls...
What I think is that it was just meant to show higher frequency and lower frequency but then again why would it decrease if the car hasnt passed the spectator yet...... edexcel pls...
I think they have made a mistake here :P just wait for ms to come out and they will be apologizing us xD