Rearrange 5y-3x-4=0 to get y=mx+c? Help please

How do you do it? I can do it normally, just I cannot rearrange it with the 0.

Can someone also explain to me what the 0 does please, and if it means anything?

Thanks!

Reply 1

BIGJohnson777

11

take -3x and -4 to the right side with the change of signs and divide all by 5.

Reply 2

BIGJohnson777

11

0 makes it an equation that you can solve for y etc.

Y = 3/5x +20

Original post by vector12

How do you do it? I can do it normally, just I cannot rearrange it with the 0.

Can someone also explain to me what the 0 does please, and if it means anything?

Thanks!

if you can't do this question and you want to actually learn how to do it, instead of just getting your homework completed. Watch this - https://www.youtube.com/watch?time_continue=827&v=BekcPu_3Bqw

Reply 5

zainyyyyy

14

5y-3x-4=0 to make y=mx+C you have to identify what mx and c is

m is -3x and c is -4

so you have to make 5y the subject

move the -3x to the right side by adding both sides by 3x

so its 5y-4=3x

then move -4 to the other side so 5y=3x+4

then divide by 5 to make 5y, y so then its y=3/5x+4/5

Reply 6

Naruke

11

Original post by Pinkberry_y

Y = 3/5x +20

good try

Reply 7

Treblebee

18

5y - 3x - 4 = 0
5y-3x = 4
5y = 3x + 4
y = 3x/5 + 4/5
ta-daa! :smile:

Reply 8

vector12

OP

10

Original post by zainyyyyy

5y-3x-4=0 to make y=mx+C you have to identify what mx and c is

m is -3x and c is -4

so you have to make 5y the subject

move the -3x to the right side by adding both sides by 3x

so its 5y-4=3x

then move -4 to the other side so 5y=3x+4

then divide by 5 to make 5y, y so then its y=3/5x+4/5

Thanks. SO when you initally move the -3x to the right side, the 0 then disappears from the equation?

Reply 9

clarkey500

17

Ok we can do this step by step:

5y-3x-4=0
(+4) 5y-3x=4 (+4)
(+3x) 5y=3x+4 (+3x)
(/5) y= (3/5)x + 4/5 (/5)

So:

y = (3/5)x +4/5

Original post by Pinkberry_y

Y = 3/5x +20

Original post by zainyyyyy

5y-3x-4=0 to make y=mx+C you have to identify what mx and c is

m is -3x and c is -4

so you have to make 5y the subject

move the -3x to the right side by adding both sides by 3x

so its 5y-4=3x

then move -4 to the other side so 5y=3x+4

then divide by 5 to make 5y, y so then its y=3/5x+4/5

Original post by clarkey500

Ok we can do this step by step:5y-3x-4=0(+4) 5y-3x=4 (+4)(+3x) 5y=3x+4 (+3x)(/5) y= (3/5)x + 4/5 (/5)So:y = (3/5)x +4/5

Original post by Treblebee

5y - 3x - 4 = 05y-3x = 45y = 3x + 4y = 3x/5 + 4/5ta-daa! :smile:

Don't post full solutions. That's of no use if OP doesn't learn through their own thinking and practice.

Reply 11

vector12

OP

10

Original post by Naruke

if you can't do this question and you want to actually learn how to do it, instead of just getting your homework completed. Watch this - https://www.youtube.com/watch?time_continue=827&v=BekcPu_3Bqw

It's not homework. I am just re-going over some old topics just to recap in my free time, and am looking for the solution so that I can see what happens to the 0.

Reply 12

Pinkberry_y

19

Original post by Naruke

good try

I dropped maths at AS I don't know the ins and outs of algebra anymore bruh

Reply 13

vector12

OP

10

Original post by clarkey500

Ok we can do this step by step:

5y-3x-4=0
(+4) 5y-3x=4 (+4)
(+3x) 5y=3x+4 (+3x)
(/5) y= (3/5)x + 4/5 (/5)

So:

y = (3/5)x +4/5

Thank you. I wasn't sure what happened to the 0, but it seems that once you move the -4 to the other side and it becomes +4 to cancel it out, that then makes the 0 disappear from the equation and gets rid of it?

So basically, the 0 is gotten rid of once you move one of the subjects to the right side of the equation, and it is just a placeholder after the = sign?

Reply 14

Pinkberry_y

19

Original post by RDKGames

Don't post full solutions. That's of no use if OP doesn't learn through their own thinking and practice.

Yes sir

Reply 15

Treblebee

18

Original post by RDKGames

Don't post full solutions. That's of no use if OP doesn't learn through their own thinking and practice.

My apologies! I guess I just thought that OP has probably spent some time working on it, and couldn't manage it alone. Sry, anyway... I'll hint, next time :wink:

Reply 16

Naruke

11

Original post by Pinkberry_y

I dropped maths at AS I don't know the ins and outs of algebra anymore bruh

this is gcse maybe even KS3

Reply 17

zainyyyyy

14

Original post by vector12

Thanks. SO when you initally move the -3x to the right side, the 0 then disappears from the equation?

yeah, 0+3x=3x

Reply 18

zainyyyyy

14

Original post by RDKGames

Don't post full solutions. That's of no use if OP doesn't learn through their own thinking and practice.

although i agree with you to an extent, but this time last year i was also going on the internet to do this and as there was no solutions i just copied the answer. but as i wrote the explanation hopefully it'll help him

Original post by zainyyyyy

although i agree with you to an extent, but this time last year i was also going on the internet to do this and as there was no solutions i just copied the answer. but as i wrote the explanation hopefully it'll help him

Whether you agree with me or not is irrelevant. Posting full solutions on this forum is against its rules. Just hint the OP in the right direction next time.

Rearrange 5y-3x-4=0 to get y=mx+c? Help please

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