C1 MEI Wednesday 16th May 2012

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yhh but im pretty sure -20 is right because some of the past papers have a similar question and thats how theyve done it.

nah you get -20 when you solve the equation involving x^3, when y=g(x) is a translation of y=f(x) which was an equation involving 2x^3, i did the same thingas you :frown:

Reply 181

Alotties

Original post by Lifeisgood:)

So the y intercept was -10, not -5?

Yes, I got -10 :smile:

Original post by superduperr

why is it (2x-5)??? :frown:

Because it was (x-5/2) which is the same as (2x-5)

Original post by jonny7bell

yeah thats what i did. Did you plus or minus the 3 from the roots in 12 iv?

I got the same as you, so whatever you did :tongue:

Reply 182

Axion

Original post by superduperr

im pretty sure its just square root of 3a/2c. sorry :frown:

Is square root (3/2a/c) correct?

Failed that paper!

Original post by ss2012

Failed that paper!

join the club

:party:

Reply 185

Alotties

Original post by Axion

Is square root (3/2a/c) correct?

If you have to simplify it fully, wouldn't you have to move the double division and make it 3ac/2? :smile:

Reply 186

wahimbay98

Original post by gaydeliya

sorry, that's edexel..

oh thank god

Reply 187

username537823

anyone here do ocr mei numerical methods today? :smile:

Reply 188

timincognito

Do you guys reckon that most people wouldve found that paper harder or easier than the C1 in January? ie. Do you reckon the grade boundaries will be higher or lower than January?

Reply 189

toddyvedda

Original post by superduperr

why is it (2x-5)??? :frown:

because they asked it for a translation of y=f(x) where it was y= 2x^3, so in order to get the 2x^3 one of the brackets needed a 2x in it, so annoyed i didn't see that

Reply 190

toddyvedda

Original post by timincognito

Do you guys reckon that most people wouldve found that paper harder or easier than the C1 in January? ie. Do you reckon the grade boundaries will be higher or lower than January?

about the same i would guess :smile:

Reply 191

superduperr

Original post by Axion

Is square root (3/2a/c) correct?

no dont think so...

Reply 192

bossman42

for the K question... wasn't the formula
b^2-4ac < 0 not >, because there weren't any real roots??

Reply 193

Alotties

Original post by timincognito

Do you guys reckon that most people wouldve found that paper harder or easier than the C1 in January? ie. Do you reckon the grade boundaries will be higher or lower than January?

Around the same, I did it in Jan and found them around the same difficulty! Well the section B of this was easier imo but section A was slightly harder than usual.

Reply 194

George_

Original post by bossman42

for the K question... wasn't the formula
b^2-4ac < 0 not >, because there weren't any real roots??

That's correct. I got -root5<k<+root5 for that question.

Reply 195

toddyvedda

Original post by bossman42

for the K question... wasn't the formula
b^2-4ac < 0 not >, because there weren't any real roots??

yeah and you got something like -sqrt5 < k < sqrt5 :smile:

Reply 196

abdus110

no ppl it is -20 whetever question u on about cause i checked it on my graphics calculator afterwards and askd the teacher that 2x-5 whatever is crap

Reply 197

zingoman

Anyone got an unofficial Mark Scheme?

Reply 198

superduperr

Original post by toddyvedda

because they asked it for a translation of y=f(x) where it was y= 2x^3, so in order to get the 2x^3 one of the brackets needed a 2x in it, so annoyed i didn't see that