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    3x+1........-..........2........+......4
    (x+2)^3........(x+2)^2........(x+2)

    I got the answer
    (4x+13)(x+1)
    (x+2)^3

    But the answer in the book has (x+2)^2 as the denominator... Is this a typo?
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    I'm sorry but you need to use LateX, I have no idea what that equation is meant to be...
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    (Original post by fayled)
    3x+1........-............2........+........4
    (x+2)^3........(x+2)^2........(x+2)

    I got the answer
    (4x+13)(x+1)
    (x+2)^3

    But the answer has (x+2)^2 as the denominator... Is this a typo?
    Yes.
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    (Original post by flown_muse)
    I'm sorry but you need to use LateX, I have no idea what that equation is meant to be...
    Sorry about that, I tried. How do I use lateX?
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    (Original post by Mr M)
    That question does not give your answer or the answer you say they have provided. Typo?
    I meant the answer given in the textbook was squared rather than cubed as I'd got...
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    I got what you got.
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    (Original post by fayled)
    I meant the answer given in the textbook was squared rather than cubed as I'd got...
    Your answer is correct. Computer fail on my part.
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    (Original post by fayled)
    Sorry about that, I tried. How do I use lateX?
    Here you go:

    http://www.thestudentroom.co.uk/wiki/LaTex :yep:

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