1. this is comparing compounds with different metals 2. do you understand any of it or not? You can't just quote papers at me. Use them to find out the answer.
Because its hexagonal structure makes it easy for electron to go through it thus conducting electricity. What is the product of butanol and ethanoic acid?
Because its hexagonal structure makes it easy for electron to go through it thus conducting electricity. What is the product of butanol and ethanoic acid?
Because its hexagonal structure makes it easy for electron to go through it thus conducting electricity. What is the product of butanol and ethanoic acid?
1. this is comparing compounds with different metals 2. do you understand any of it or not? You can't just quote papers at me. Use them to find out the answer.
1. Correct, but is does talk about the structure of mercuryoxide, which is part of your question and could explain this part. 2. Of course I do not understand the article into every detail but I do understand the idea.
I was just asking if this was on the right track to an answer, but I do understand it makes look a bit lazy, sorry for that. I'll try to formulate an answer using your hint.
The expected NMR shift of aromatic protons is around 7-8 ppm. What is the typical shift of protons positioned directly above the centre of a benzene ring, and why does it differ from the normal range?
1. Correct, but is does talk about the structure of mercuryoxide, which is part of your question and could explain this part. 2. Of course I do not understand the article into every detail but I do understand the idea.
I was just asking if this was on the right track to an answer, but I do understand it makes look a bit lazy, sorry for that. I'll try to formulate an answer using your hint.
No I'm not accusing you of being lazy, just saying that it doesn't count as an answer. Sorry but i'm not going to read the whole paper when the abstract implies that the answer isn't in there. The answer I'm looking for isn't anything to do with what the structure of HgO is apart from that it is less symmetric than the structure of HgS.
OK, big clue..... I knew this was going to be needed!!!
The distortion is driven by mixing of the metal and anion orbitals. In the regular structure the anion p cannot interact with the metal levels, it is symmetry disallowed. In the less symmetric environment of the distorted structure the mixing is symmetry allowed. Now rationalise why this happens for HgO and not HgS!!!
I think my question was less unreasonable than yours.
It's straight out of lecture notes..... seeing as you're clearly at the same uni as me (given how you know me from somewhere) you should be able to look this up eaisly.
Because its hexagonal structure makes it easy for electron to go through it thus conducting electricity. What is the product of butanol and ethanoic acid?
No I'm not accusing you of being lazy, just saying that it doesn't count as an answer. Sorry but i'm not going to read the whole paper when the abstract implies that the answer isn't in there. The answer I'm looking for isn't anything to do with what the structure of HgO is apart from that it is less symmetric than the structure of HgS.
OK, big clue..... I knew this was going to be needed!!!
The distortion is driven by mixing of the metal and anion orbitals. In the regular structure the anion p cannot interact with the metal levels, it is symmetry disallowed. In the less symmetric environment of the distorted structure the mixing is symmetry allowed. Now rationalise why this happens for HgO and not HgS!!!
It's straight out of lecture notes..... seeing as you're clearly at the same uni as me (given how you know me from somewhere) you should be able to look this up eaisly.
I'm pretty sure that you can prove these sorts of distortions are always lead to a reduction of the p orbital energy (due to the lowering in energy of the occupied p orbitals). However whether or not the distortion occur depend on whether this outweighs the increase in energy of the other interactions. Whether this will occur depends on the strength of the other Hg-O/S interactions. You'd expect Hg-S interactions to be stronger than Hg-O (due to the energies of the bonding electrons) and so the distortion would not be favoured in Hg-S.